Samarium(III) phosphate

Samarium(III) phosphate is an inorganic compound, with the chemical formula of SmPO₄. It is one of the phosphates of samarium.

Samarium(III) phosphate

Identifiers
CAS Number	13465-57-1 Y monohydrate: 14913-18-9
3D model (JSmol)	Interactive image monohydrate: Interactive image
ChemSpider	13931016
ECHA InfoCard	100.033.348
EC Number	236-698-0
PubChem CID	13710715 monohydrate: 16217379
CompTox Dashboard (EPA)	DTXSID10928706
InChI InChI=1S/H3O4P.Sm/c1-5(2,3)4;/h(H3,1,2,3,4);/q;+3/p-3 Key: BJRVEOKYZKROCC-UHFFFAOYSA-K monohydrate: InChI=1S/H3O4P.H2O.Sm/c1-5(2,3)4;;/h(H3,1,2,3,4);1H2;/q;;+3/p-3 Key: GIUBLDXWAJRBHC-UHFFFAOYSA-K
SMILES [O-]P(=O)([O-])[O-].[Sm+3] monohydrate: O.[O-]P(=O)([O-])[O-].[Sm+3]
Properties
Chemical formula	O4PSm
Molar mass	245.33 g·mol−1
Appearance	solid
Density	5.83 g·cm−3
Solubility in water	insoluble
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa). Infobox references

Preparation

Samarium(III) phosphate can be obtained by reacting sodium metaphosphate with any soluble samarium(III) salt:

${\displaystyle {\mathsf {SmCl_{3}+NaPO_{3}+H_{2}O\ {\xrightarrow {}}\ 2SmPO_{4}\downarrow +NaCl+2HCl}}}$

Samarium(III) phosphate can also be obtained by reacting phosphoric acid and samarium(III) chloride.^[1]

Properties

Samarium(III) phosphate reacts with sodium fluoride at 750 °C to form Na₂SmF₂PO₄.^[2] Samarium(III) phosphate forms crystals of the monoclinic crystal system, with space group P2₁/n, and lattice parameters a = 0.6669 nm, b = 0.6868 nm, c = 0.6351 nm, β = 103.92 °, Z = 4.^[3]