Seward Township, Kosciusko County, Indiana

Seward Township is one of seventeen townships in Kosciusko County, Indiana, United States. As of the 2020 census, its population was 2,280 (down from 2,567 at 2010^[4]) and it contained 1,357 housing units.

Seward Township
Township
Coordinates: 41°06′29″N 85°56′46″W
Country	United States
State	Indiana
County	Kosciusko
Government
• Type	Indiana township
Area
• Total	36.27 sq mi (93.9 km2)
• Land	34.98 sq mi (90.6 km2)
• Water	1.3 sq mi (3 km2)
Elevation [1]	876 ft (267 m)
Population  (2020)[2]
• Total	2,280
• Density	73.4/sq mi (28.3/km2)
Time zone	UTC-5 (Eastern (EST))
• Summer (DST)	UTC-4 (EDT)
FIPS code	18-68796[3]
GNIS feature ID	453840

Seward Township was organized in 1859.^[5]

Geography

According to the 2010 census, the township has a total area of 36.27 square miles (93.9 km²), of which 34.98 square miles (90.6 km²) (or 96.44%) is land and 1.3 square miles (3.4 km²) (or 3.58%) is water.^[4]

Cities and towns

• Burket