Summertown, Georgia

Summertown is a city in Emanuel County, Georgia, United States. The population was 121 in 2020.

Summertown, Georgia
City
Location in Emanuel County and the state of Georgia
Coordinates: 32°44′48″N 82°16′34″W
Country	United States
State	Georgia
County	Emanuel
Area [1]
• Total	0.79 sq mi (2.05 km2)
• Land	0.79 sq mi (2.04 km2)
• Water	0.00 sq mi (0.01 km2)
Elevation	253 ft (77 m)
Population  (2020)
• Total	121
• Density	153.94/sq mi (59.40/km2)
Time zone	UTC-5 (Eastern (EST))
• Summer (DST)	UTC-4 (EDT)
ZIP code	30401
Area code	478
FIPS code	13-74348[2]
GNIS feature ID	0323743[3]

History

Summertown was originally built up as a summer retreat, hence the name.^[4] The Georgia General Assembly incorporated Summertown as a town in 1906.^[5]

Geography

Summertown is located in northern Emanuel County at 32°44′48″N 82°16′34″W (32.746532, -82.276182).^[6] Georgia State Route 56 passes through the east side of the city limits, leading north 5 miles (8 km) to Midville and south 11 miles (18 km) to Swainsboro, the county seat.

According to the United States Census Bureau, Summertown has a total area of 0.77 square miles (2.0 km²), of which 0.004 square miles (0.01 km²), or 0.54%, is water.^[7]

Demographics

Historical population

Census	Pop.	Note	%±
1970	159		—
1980	215		35.2%
1990	153		−28.8%
2000	140		−8.5%
2010	160		14.3%
2020	121		−24.4%
U.S. Decennial Census[8]

As of the census^[2] of 2000, there were 140 people, 48 households, and 34 families residing in the town. By 2020, its population declined to 121.