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Trigonometric moment problem
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In mathematics, the trigonometric moment problem is formulated as follows: given a sequence , does there exist a distribution function on the interval such that:[1][2] with for . In case the sequence is finite, i.e., , it is referred to as the truncated trigonometric moment problem.[3]
An affirmative answer to the problem means that are the Fourier-Stieltjes coefficients for some (consequently positive) Radon measure on .[4][5]
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Characterization
The trigonometric moment problem is solvable, that is, is a sequence of Fourier coefficients, if and only if the (n + 1) × (n + 1) Hermitian Toeplitz matrix with for , is positive semi-definite.[6]
The "only if" part of the claims can be verified by a direct calculation. We sketch an argument for the converse. The positive semidefinite matrix defines a sesquilinear product on , resulting in a Hilbert space of dimensional at most n + 1. The Toeplitz structure of means that a "truncated" shift is a partial isometry on . More specifically, let be the standard basis of . Let and be subspaces generated by the equivalence classes respectively . Define an operator by Since can be extended to a partial isometry acting on all of . Take a minimal unitary extension of , on a possibly larger space (this always exists). According to the spectral theorem,[7][8] there exists a Borel measure on the unit circle such that for all integer k For , the left hand side is As such, there is a -atomic measure on , with (i.e. the set is finite), such that[9] which is equivalent to
for some suitable measure .
Parametrization of solutions
The above discussion shows that the trigonometric moment problem has infinitely many solutions if the Toeplitz matrix is invertible. In that case, the solutions to the problem are in bijective correspondence with minimal unitary extensions of the partial isometry .
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See also
Notes
References
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