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Tsankov Island

Antarctic island From Wikipedia, the free encyclopedia

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Tsankov Island (Bulgarian: Цанков остров, romanized: Tsankov ostrov, IPA: [t͡sɐnˈkɔf ˈɔstrof]) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.[1]

Quick Facts Geography, Location ...

The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.[1]

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Location

Tsankov Island is located at 65°03′58″S 64°08′38″W, which is 293 m northwest of Stego Island, 175 m east of Bodloperka Island, 1.18 km southeast of Sprey Island and 1.25 km west-southwest of Taralezh Island. British mapping in 2001.

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Notes

References

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