Vanadium(II) iodide

Vanadium(II) iodide is the inorganic compound with the formula VI₂. It is a black micaceous solid. It adopts the cadmium iodide structure, featuring octahedral V(II) centers.^[1] The hexahydrate [V(H₂O)₆]I₂, an aquo complex, is also known. It forms red-violet crystals. The hexahydrate dehydrates under vacuum to give a red-brown tetrahydrate with the formula V(H₂O)₄I₂.^[2]

Vanadium(II) iodide

Identifiers
CAS Number	15513-84-5 Y
3D model (JSmol)	Interactive image
ChemSpider	76640
ECHA InfoCard	100.035.935
EC Number	239-545-6
PubChem CID	84959
CompTox Dashboard (EPA)	DTXSID40935145
InChI InChI=1S/2HI.V/h2*1H;/q;;+2/p-2 Key: OJFNQCZRUJTCOZ-UHFFFAOYSA-L
SMILES [V+2].[I-].[I-]
Properties
Chemical formula	VI2
Appearance	black mica-like
Density	5.44 g/cm3
Related compounds
Other anions	vanadium(II) chloride, vanadium(II) bromide
Related compounds	vanadium(III) iodide
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa). Infobox references

Preparation

The original synthesis of VI₂ involved reaction of the elements.^[1]

Solvated vanadium(II) iodides can be prepared by reduction of vanadium(III) chlorides with trimethylsilyl iodide.^[3] It reacts with anhydrous ammonia to give the hexaammine complex.^[4]