Ytterbium(II) fluoride

Ytterbium(II) fluoride is a binary inorganic compound of ytterbium and fluorine with the chemical formula YbF₂.^[2][3][4]

Ytterbium(II) fluoride

Names
Other names Ytterbium difluoride
Identifiers
CAS Number	15192-18-4
3D model (JSmol)	Interactive image
ChemSpider	19971765
PubChem CID	21115929
InChI InChI=1S/2FH.Yb/h2*1H;/q;;+2/p-2 Key: DZIGMZRMIWDBCU-UHFFFAOYSA-L
SMILES [F-].[F-].[Yb+2]
Properties
Chemical formula	F2Yb
Molar mass	211.042 g·mol−1
Appearance	gray crystals
Density	g/cm3
Melting point	1,407 °C (2,565 °F; 1,680 K)
Boiling point	2,380 °C (4,320 °F; 2,650 K)
Solubility in water	insoluble
Structure[1]
Crystal structure	Fluorite structure
Space group	Fm3m (No. 225)
Lattice constant	a = 559.93 pm
Formula units (Z)	4
Related compounds
Other anions	Ytterbium(II) chloride Ytterbium(II) iodide
Other cations	Samarium(II) fluoride Europium(II) fluoride Thulium(II) fluoride
Related compounds	Ytterbium(III) fluoride
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa). Infobox references

Synthesis

Ytterbium(II) fluoride can be obtained by reacting ytterbium(III) fluoride with ytterbium or hydrogen.

2YbF₃ + Yb → 3YbF₂

2YbF₃ + H₂ → 2YbF₂ + 2HF

Physical properties

Ytterbium(II) fluoride is a gray solid and crystallizes in the so-called fluorite type analogous to calcium fluoride with a unit cell a axis of 559.46 pm. In the crystal structure of ytterbium(II) fluoride, the Yb²⁺ cation is surrounded by eight F⁻ anions in the form of a cube, which is tetrahedrally surrounded by four Yb²⁺.^[5]