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Zirconium(IV) bromide
Chemical compound From Wikipedia, the free encyclopedia
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Zirconium(IV) bromide is the inorganic compound with the formula ZrBr4. This colourless solid is the principal precursor to other Zr–Br compounds.
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Preparation and properties
ZrBr4 is prepared by the action of bromine on zirconium oxide via a carbothermic reaction:[1]
- ZrO2 + 2 C + 2 Br2 → ZrBr4 + 2 CO
Like many related tetrahalides, it is purified by sublimation.
It can also be prepared by treatment of the borohydride complex with hydrogen bromide:[2]
- Zr(BH4)4 + 4 HBr → ZrBr4 + 4 H2 + 2 B2H6
Like related tetrabromides of Ti and Hf, ZrBr4 hydrolyzes readily to give the oxybromide, with release of hydrogen bromide.
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Structure
No single crystal X-ray study of ZrBr4 has been described. Some reports suggest that it is isostructural with TiCl4 and TiBr4, featuring tetrahedral metal centers.[3] Other studies indicate a polymeric structure.[4] ZrCl4 is polymeric in the solid state, featuring octahedral Zr centers.[5]
References
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