Cuba, New York
town in Allegany County, New York, United States From Wikipedia, the free encyclopedia
Cuba is a town in Allegany County, New York, United States. As of the 2020 United States Census, the total population was 3,126.[2]
Cuba, New York | |
|---|---|
 Town center along Genesee Street | |
  Cuba Location of Cuba in New York  Cuba Cuba (the United States) | |
| Coordinates: 42°13′04″N 78°16′31″W | |
| Country | United States |
| State | New York |
| County | Allegany |
| Area | |
| • Total | 35.80 sq mi (92.73 km2) |
| • Land | 35.10 sq mi (90.91 km2) |
| • Water | 0.70 sq mi (1.82 km2) |
| Population | |
| • Total | 3,126 |
| • Density | 89.06/sq mi (34.39/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| FIPS code | 36-003-19367 |
| Website | https://www.cubany.org/ |
References
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