Yuzhno-Sakhalinsk

city in far-eastern Russia From Wikipedia, the free encyclopedia

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Yuzhno-Sakhalinsk (Russian: Ю́жно-Сахали́нск, IPA: [ˈjuʐnə səxɐˈlʲinsk] (audio speaker iconlisten), literally "South Sakhalin City") is a city on Sakhalin island. It is also the administrative center of Sakhalin Oblast, Russia. It is in the Far East part of Russia. It is north of Japan.[11] Gas and oil extraction and processing are the main industries of the island. It was named Vladimirovka (Влади́мировка) from 1882 to 1905, then Toyohara (Japanese: 豊原市, Hepburn: Toyohara-shi) when Imperial Japan controlled it from 1905 to 1946. As of the 2010 Census, its population was 181,728.[5]

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History

Yuzhno-Sakhalinsk started as a small Russian settlement called Vladimirovka. It was founded by convicts in 1882.[2] In the Treaty of Portsmouth in 1905, the southern part of Sakhalin was given to Japan. This treaty ended the Russo-Japanese War of 1904–1905. Because Vladimirovka was in southern Sakhalin, it was given to Japan. Vladimirovka was renamed Toyohara (meaning "bountiful plain" in Japanese).

During the Soviet–Japanese War within World War II, the city was taken by Soviet soldiers. After the war, it was given to the Soviet Union. It was renamed Yuzhno-Sakhalinsk and given town status in 1946.[2]


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Demographics

Population

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Most citizens are ethnic Russians, but there is also many Korean Russians. There are also smaller numbers of indigenous minorities, such as Ainu, Nivkhs and Oroks.

Geography

The city is on the Susuya River. It is the largest city on Sakhalin. It is the only one with more than 100,000 inhabitants on the island.

Twin towns and sister cities

Yuzhno-Sakhalinsk is twinned with:

References

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