Keosauqua, Iowa

City in Iowa, United States / From Wikipedia, the free encyclopedia

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Keosauqua (/ˌkəˈsɔːkwə/ KEE-ə-SAW-kwə) is a city in Van Buren County, Iowa, United States. The population was 936 at the time of the 2020 census.[3] It is the county seat of Van Buren County.[4]

Quick facts: Keosauqua, Iowa, Country, State, County, Area...
Keosauqua, Iowa
City
Keosauqua welcome sign
Keosauqua welcome sign
Location of Keosauqua, Iowa
Location of Keosauqua, Iowa
Coordinates: 40°44′05″N 91°57′37″W
CountryFlag_of_the_United_States_%2823px%29.png United States
StateFlag_of_Iowa.svg Iowa
CountyVan Buren
Area
  Total1.58 sq mi (4.10 km2)
  Land1.46 sq mi (3.78 km2)
  Water0.12 sq mi (0.32 km2)
Elevation633 ft (193 m)
Population
 (2020)
  Total936
  Density641.54/sq mi (247.74/km2)
Time zoneUTC-6 (Central (CST))
  Summer (DST)UTC-5 (CDT)
ZIP code
52565
Area code319
FIPS code19-40935
GNIS feature ID2395517[2]
Websitekeosauqua.com
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