Vilkitsky Island (East Siberian Sea)
Island in the East Siberian Sea / From Wikipedia, the free encyclopedia
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For other islands and geographic features called "Vilkitsky", see Vilkitsky (disambiguation).
Vilkitsky Island (Russian: Остров Вильки́цкого, romanized: Ostrov Vilkitskogo; Yakut: Вилькицкай Aрыыта, romanized: Vil'kitskay Arııta) is the southernmost island of the De Long group in the northern part of the East Siberian Sea. The nearest island is Zhokhov Island. Administratively Vilkitsky Island belongs to Yakutia, an administrative division of the Russian Federation.[1]
Quick Facts Native name:, Geography ...
Map of the De Long Islands. | |
![]() Map showing the location of the group | |
Geography | |
Location | East Siberian Sea |
Coordinates | 75°42′N 152°30′E |
Archipelago | De Long Islands |
Total islands | 5 |
Area | 1.5 km2 (0.58 sq mi) |
Length | 2 km (1.2 mi) |
Width | 1 km (0.6 mi) |
Highest elevation | 70 m (230 ft) |
Administration | |
Russia | |
Federal subject | Far Eastern Federal District |
Republic | Yakutia |
Demographics | |
Population | uninhabited |
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The island is named after Russian hydrographer Andrey Vilkitsky.[2]