1800 United States presidential election in Kentucky

Main article: 1800 United States presidential election

The 1800 United States presidential election in Kentucky took place between October 31 and December 11, 1800, as part of the 1800 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.^[1]

1800 United States presidential election in Kentucky

← 1796 October 31 – December 11, 1800 1804 →

Nominee Thomas Jefferson John Adams Party Democratic-Republican Federalist Home state Virginia Massachusetts Running mate Aaron Burr Charles C. Pinckney Electoral vote 4 0 Popular vote 119 0 Percentage 100.00% 0.00%

Kentucky cast four electoral votes for the Democratic-Republican candidate and incumbent Vice President Thomas Jefferson over the Federalist candidate and incumbent President John Adams. The electoral votes for Vice president were cast for Jefferson's running mate Aaron Burr from New York. The state was divided into two electoral districts with two electors each, whereupon each district's voters chose the electors.^[2]

Results

1800 United States presidential election in Kentucky[3]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	Thomas Jefferson	119	100.00%	4
	Federalist	John Adams (incumbent)	0	0.00%	0
Totals			119	100.00%	4

See also

• United States presidential elections in Kentucky