1804 United States presidential election in Kentucky

Main article: 1804 United States presidential election

The 1804 United States presidential election in Kentucky took place between November 2 and December 15, 1804, as part of the 1804 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President. Kentucky had gained four electors compared to the previous election in 1800.^[1]

1804 United States presidential election in Kentucky

← 1800 November 2 – December 15, 1804 1808 →

Nominee Thomas Jefferson Charles C. Pinckney Party Democratic-Republican Federalist Home state Virginia South Carolina Running mate George Clinton Rufus King Electoral vote 8 0 Popular vote 5,080 0 Percentage 100.00% 0.00%

Kentucky cast eight electoral votes for the Democratic-Republican candidate and incumbent President Thomas Jefferson over the Federalist candidate Charles C. Pinckney. The electoral votes for Vice president were cast for Jefferson's running mate George Clinton from New York. The state was divided into two electoral districts with four electors each, whereupon each district's voters chose the electors.^[2]

Results

1804 United States presidential election in Kentucky[3]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	Thomas Jefferson (incumbent)	5,080	100.0%	8
	Federalist	Charles C. Pinckney	0	0.00%	0
Totals			5,080	100.0%	8

See also

• United States presidential elections in Kentucky