1832 United States presidential election in Kentucky

Main article: 1832 United States presidential election

The 1832 United States presidential election in Kentucky took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

1832 United States presidential election in Kentucky

← 1828 November 2 – December 5, 1832 1836 →

Nominee Henry Clay Andrew Jackson Party National Republican Democratic Home state Kentucky Tennessee Running mate John Sergeant Martin Van Buren Electoral vote 15 0 Popular vote 43,449 36,292 Percentage 54.49% 45.51%

County Results Clay   50–60%   60–70%   70–80%   80–90% Jackson   50–60%   60–70%   70–80%   80–90% No Data/Vote

Kentucky voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Kentucky by a margin of 8.98%. His victory was likely influenced by the home state advantage he received from his native state. Kentucky and South Carolina were the only 2 states Jackson lost in 1832 that he had won in the previous cycle.

Results

1832 United States presidential election in Kentucky[1]
Party		Candidate	Votes	Percentage	Electoral votes
	National Republican	Henry Clay	43,449	54.49%	15
	Democratic	Andrew Jackson (incumbent)	36,292	45.51%	0
Totals			79,741	100.0%	15