1836 United States presidential election in Kentucky

Main article: 1836 United States presidential election

The United States presidential election in Kentucky was held from November 7–9, 1836 as part of the 1836 United States presidential election.^[1] Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

1836 United States presidential election in Kentucky

← 1832 November 7–9, 1836 1840 →

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Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate Francis Granger Richard M. Johnson Electoral vote 15 0 Popular vote 36,861 33,229 Percentage 52.59% 47.41%

County Results Harrison   50–60%   60–70%   70–80%   80–90% Van Buren   50–60%   60–70%   70–80%   80–90%

Kentucky voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Kentucky by a margin of 5.18%.

Results

1836 United States presidential election in Kentucky[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Whig	William Henry Harrison	36,861	52.59%	15
	Democratic	Martin Van Buren	33,229	47.41%	0
Totals			70,090	100.0%	15