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1836 United States presidential election in New York

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1836 United States presidential election in New York
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A presidential election was held in New York from November 7–9, 1836 as part of the 1836 United States presidential election.[2] Voters chose 42 representatives, or electors to the Electoral College, who voted for President and Vice President.

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New York voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New York by a margin of 9.26%. Saratoga County would not vote Democratic again until 1964.

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