1876 United States presidential election in Delaware

Main article: 1876 United States presidential election

The 1876 United States presidential election in Delaware took place on November 7, 1876, as part of the 1876 United States presidential election. Delaware voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.^[1]

1876 United States presidential election in Delaware

← 1872 November 7, 1876 1880 →

Nominee Samuel J. Tilden Rutherford B. Hayes Party Democratic Republican Home state New York Ohio Running mate Thomas A. Hendricks William A. Wheeler Electoral vote 3 0 Popular vote 13,381 10,752 Percentage 55.45% 44.55%

County Results Tilden   50–60%   60–70%

President before election Ulysses S. Grant Republican Elected President Rutherford B. Hayes Republican

Delaware was won by Samuel J. Tilden, the former governor of New York (D–New York), running with Thomas A. Hendricks, the governor of Indiana and future vice president, with 55.45% of the popular vote, against Rutherford B. Hayes, the governor of Ohio (R-Ohio), running with Representative William A. Wheeler, with 44.55% of the vote.^[1]

Results

1876 United States presidential election in Delaware[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Samuel J. Tilden of New York	Thomas A. Hendricks of Indiana	13,381	55.45%	10	100.00%
	Republican	Rutherford B. Hayes of Ohio	William A. Wheeler of New York	10,752	44.55%	0	0.00%
Total				24,133	100.00%	3	100.00%

See also

• United States presidential elections in Delaware