1888 United States presidential election in Rhode Island

Main article: 1888 United States presidential election

The 1888 United States presidential election in Rhode Island took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

1888 United States presidential election in Rhode Island

← 1884 November 6, 1888 1892 →

Nominee Benjamin Harrison Grover Cleveland Party Republican Democratic Home state Indiana New York Running mate Levi P. Morton Allen G. Thurman Electoral vote 4 0 Popular vote 21,969 17,530 Percentage 53.88% 42.99%

County Results Harrison   50–60%

President before election Grover Cleveland Democratic Elected President Benjamin Harrison Republican

Rhode Island voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a margin of 10.89%.

Results

1888 United States presidential election in Rhode Island[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Benjamin Harrison of Indiana	Levi Parsons Morton of New York	21,969	53.88%	4	100.00%
	Democratic	Grover Cleveland of New York (incumbent)	Allen Granberry Thurman of Ohio	17,530	42.99%	0	0.00%
	Prohibition	Clinton Bowen Fisk of New Jersey	John Anderson Brooks of Missouri	1,251	3.07%	0	0.00%
	Labor	Alson Streeter of Illinois	Charles E. Cunningham of Arkansas	18	0.04%	0	0.00%
	N/A	Others	Others	7	0.02%	0	0.00%
Total				40,775	100.00%	4	100.00%

See also

• United States presidential elections in Rhode Island