1892 United States presidential election in Rhode Island

Main article: 1892 United States presidential election

The 1892 United States presidential election in Rhode Island took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

1892 United States presidential election in Rhode Island

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Nominee Benjamin Harrison Grover Cleveland Party Republican Democratic Home state Indiana New York Running mate Whitelaw Reid Adlai Stevenson I Electoral vote 4 0 Popular vote 26,975 24,336 Percentage 50.71% 45.75%

County Results Harrison   40–50%   50–60%

President before election Benjamin Harrison Republican Elected President Grover Cleveland Democratic

Rhode Island voted for the Republican nominee, incumbent President Benjamin Harrison, over the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term. Harrison won the state by a narrow margin of 4.96%.

Results

1892 United States presidential election in Rhode Island[1]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	Benjamin Harrison of Indiana (incumbent)	Whitelaw Reid of New York	26,975	50.71%	4	100.00%
	Democratic	Grover Cleveland of New York	Adlai Ewing Stevenson I of Illinois	24,336	45.75%	0	0.00%
	Prohibition	John Bidwell of California	James Cranfill of Texas	1,654	3.11%	0	0.00%
	Populist	James Baird Weaver of Iowa	James Gaven Field of Virginia	228	0.43%	0	0.00%
	N/A	Others	Others	3	0.01%	0	0.00%
Total				53,196	100.00%	4	100.00%

See also

• United States presidential elections in Rhode Island