Top Qs
Timeline
Chat
Perspective

1936 United States presidential election in Delaware

From Wikipedia, the free encyclopedia

1936 United States presidential election in Delaware
Remove ads

The 1936 United States presidential election in Delaware was held on November 3, 1936. The state voters chose three electors to the Electoral College, who voted for president and vice president.

Quick facts Nominee, Party ...

Delaware voted for Democratic Party candidate and incumbent President Franklin D. Roosevelt, who defeated Republican nominee, Kansas Governor Alf Landon. Roosevelt won the state by a margin of 9.77%, marking the first time since 1912 that the state voted for a Democratic presidential candidate, and the first time since 1888 that a Democrat carried the state with an outright majority.

While Landon lost the state, the 44.85% of the popular vote made Delaware his fifth strongest state in the 1936 election in terms of popular vote percentage after Vermont, Maine, New Hampshire and Kansas.[1]

This election marked Delaware's transition into a bellwether state: for the rest of the 20th century, it would vote for a losing candidate only once (in 1948). Once the century rolled around, it came to be regarded as a solidly blue state.

Remove ads

Results

More information Party, Candidate ...

Results by county

More information County, Dem ...

Counties that flipped from Republican to Democratic

Remove ads

See also

References

Loading related searches...

Wikiwand - on

Seamless Wikipedia browsing. On steroids.

Remove ads