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2019 Kobe Challenger – Doubles

Tennis tournament From Wikipedia, the free encyclopedia

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Gonçalo Oliveira and Akira Santillan were the defending champions[1] but chose to defend their title with different partners. Oliveira partnered Brydan Klein but withdrew in the first round. Santillan partnered Bradley Mousley but lost in the first round to Nam Ji-sung and Song Min-kyu.

Quick Facts Doubles, Final ...

Purav Raja and Ramkumar Ramanathan won the title after defeating André Göransson and Christopher Rungkat 7–6(8–6), 6–3 in the final.

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Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 Australia M Reid
Australia L Saville
0 6 [9]
WC Japan T Ichikawa
Japan S Watanabe
6 5 [4] Japan T Matsui
Japan Yo Watanuki
6 4 [11]
Japan T Matsui
Japan Yo Watanuki
3 7 [10] Japan T Matsui
Japan Yo Watanuki
3 4
4 India P Raja
India R Ramanathan
4 4 India P Raja
India R Ramanathan
6 6
Thailand Sa Ratiwatana
Thailand So Ratiwatana
2r 4 India P Raja
India R Ramanathan
7 2 [10]
South Korea J-s Nam
South Korea M-k Song
6 3 [10] South Korea J-s Nam
South Korea M-k Song
5 6 [7]
Australia B Mousley
Australia A Santillan
4 6 [7] 4 India P Raja
India R Ramanathan
78 6
China Y Bai
China Z Li
77 6 2 Sweden A Göransson
Indonesia C Rungkat
66 3
WC Japan Shintaro Imai
Japan T Niki
61 4 China Y Bai
China Z Li
7 6
WC Japan S Hazawa
Japan Y Shimizu
3 Chinese Taipei C-p Hsieh
Chinese Taipei T-h Yang
5 3
3 Chinese Taipei C-p Hsieh
Chinese Taipei T-h Yang
w/o China Y Bai
China Z Li
2 0
United Kingdom B Klein
Portugal G Oliveira
2 Sweden A Göransson
Indonesia C Rungkat
6 6
India A Kadhe
Spain E López Pérez
w/o India A Kadhe
Spain E López Pérez
4 2
Chinese Taipei C-h Tseng
Chinese Taipei T-l Wu
4 3 2 Sweden A Göransson
Indonesia C Rungkat
6 6
2 Sweden A Göransson
Indonesia C Rungkat
6 6
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References

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