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2019 Open Harmonie mutuelle – Doubles

2019 tennis event results From Wikipedia, the free encyclopedia

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Sander Arends and Tristan-Samuel Weissborn were the defending champions[1] but lost in the semifinals to Jonathan Eysseric and Antonio Šančić.

Quick Facts Doubles, Final ...

Jonathan Erlich and Fabrice Martin won the title after defeating Eysseric and Šančić 7–6(7–2), 7–6(7–2) in the final.

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Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 Austria P Oswald
India L Paes
6 2 [8]
United States J Cerretani
Switzerland M-A Hüsler
4 6 [10] United States J Cerretani
Switzerland M-A Hüsler
4 4
Venezuela LD Martínez
Portugal G Oliveira
62 4 ITF Spain A Artuñedo
Spain S Martos Gornés
6 6
ITF Spain A Artuñedo
Spain S Martos Gornés
77 6 ITF Spain A Artuñedo
Spain S Martos Gornés
3 4
4 Israel J Erlich
France F Martin
6 77 4 Israel J Erlich
France F Martin
6 6
Belarus A Vasilevski
Italy A Vavassori
3 64 4 Israel J Erlich
France F Martin
78 67 [10]
Australia R Junaid
Netherlands D Pel
6 6 Australia R Junaid
Netherlands D Pel
66 79 [6]
WC France E Furness
France M Guinard
4 2 4 Israel J Erlich
France F Martin
77 77
WC France Q Halys
France G Jacq
63 62 France J Eysseric
Croatia A Šančić
62 62
Netherlands S Arends
Austria T-S Weissborn
77 77 Netherlands S Arends
Austria T-S Weissborn
6 77
ITF France D Added
France A Olivetti
64 6 [10] ITF France D Added
France A Olivetti
4 65
3 United States R Galloway
United States N Lammons
77 4 [8] Netherlands S Arends
Austria T-S Weissborn
3 5
France J Eysseric
Croatia A Šančić
6 6 France J Eysseric
Croatia A Šančić
6 7
Ukraine S Stakhovsky
Poland S Walków
3 1 France J Eysseric
Croatia A Šančić
77 6
WC France M Martineau
France C Moutet
4 4 2 Monaco R Arneodo
France H Nys
64 4
2 Monaco R Arneodo
France H Nys
6 6
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References

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