2019 Santaizi ATP Challenger – Doubles

Matthew Ebden and Andrew Whittington were the defending champions but chose not to defend their title.^[1]

Doubles
2019 Santaizi ATP Challenger
Champions	Sriram Balaji Jonathan Erlich
Runners-up	Sander Arends Tristan-Samuel Weissborn
Score	6–3, 6–2

Main article: 2019 Santaizi ATP Challenger

Sriram Balaji and Jonathan Erlich won the title after defeating Sander Arends and Tristan-Samuel Weissborn 6–3, 6–2 in the final.

Seeds

1. Hsieh Cheng-peng / Christopher Rungkat (semifinals)
2. Max Purcell / Luke Saville (first round)
3. Sriram Balaji / Jonathan Erlich (champions)
4. Sander Arends / Tristan-Samuel Weissborn (final)

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• Alt = Alternate
• ITF = ITF entry
• PR = Protected ranking
• SR = Special ranking
• SE = Special exempt
• JE = Junior exempt
• JR = Junior Accelerator Programme entrant
• CO = College Accelerator Programme entrant
• NG = Next Gen Accelerator Program entrant
• w/o = Walkover
• r = Retired
• d = Defaulted

	First round							Quarterfinals							Semifinals							Final
	1	C-p Hsieh C Rungkat	64	6	[11]
		R Gonzales So Ratiwatana	77	1	[9]			1	C-p Hsieh C Rungkat	6	710
	WC	Y-h Hsu T-l Wu	7	65	[8]			WC	J Jung J Wang	4	68
	WC	J Jung J Wang	5	77	[10]										1	C-p Hsieh C Rungkat	2	3
	3	S Balaji J Erlich	6	3	[11]										3	S Balaji J Erlich	6	6
		L Margaroli V Vardhan	4	6	[9]			3	S Balaji J Erlich	6	6
		S-w Kwon T-h Yang	65	3					S Myneni R Ramanathan	4	3
		S Myneni R Ramanathan	77	6																		3	S Balaji J Erlich	6	6
		M Janvier S Robert	6	64	[10]																	4	S Arends T-S Weissborn	3	2
		D Pel H Podlipnik Castillo	1	77	[6]				M Janvier S Robert	64	6	[8]
		D Novak S Stakhovsky	6	4	[4]			4	S Arends T-S Weissborn	77	4	[10]
	4	S Arends T-S Weissborn	3	6	[10]										4	S Arends T-S Weissborn	2	6	[11]
	WC	T Chen R Ho	3	77	[3]											G Oliveira Y Uchiyama	6	3	[9]
		G Oliveira Y Uchiyama	6	63	[10]				G Oliveira Y Uchiyama	6	6
		T Matsui H Moriya	6	3	[10]				T Matsui H Moriya	4	4
	2	M Purcell L Saville	4	6	[7]