Iodyl fluoride

Iodyl fluoride is an inorganic compound of iodine, fluorine, and oxygen with the chemical formula IO₂F. It is in the form of colorless crystals. Iodyl fluoride features iodine in the oxidation state of +5. The compound was initially synthesized in 1951.^[1]

Iodyl fluoride

Names
IUPAC name Fluoro(dioxo)-λ5-iodane Iodine(V) fluoride dioxide
Identifiers
CAS Number	28633-62-7 Y
3D model (JSmol)	Interactive image
ChemSpider	57449638
PubChem CID	44546993
CompTox Dashboard (EPA)	DTXSID20659296
InChI InChI=1S/FIO2/c1-2(3)4 Key: FRYHXHDHQQGJSF-UHFFFAOYSA-N
SMILES O=I(F)=O
Properties
Chemical formula	IO2F
Molar mass	177.901 g·mol−1
Appearance	colorless crystals
Density	4.982 g/cm3
Melting point	200 °C (392 °F; 473 K)
Solubility in water	Reacts with water
Related compounds
Related compounds	Chloryl fluoride Bromyl fluoride Iodosyl pentafluoride Iodosyl trifluoride Periodyl fluoride Iodyl trifluoride
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa). Infobox references

Synthesis

Iodyl fluoride can be decomposed by iodosyl trifluoride heated to 110 °C (230 °F) in nitrogen. Since this reaction is reversible, the reaction requires constant removal of iodine pentafluoride.^[1]

2 IOF₃ ⇌ IO₂F + IF₅

It can also be obtained by dissolving iodine pentoxide, I₂O₅, in anhydrous hydrogen fluoride.^[2]

I₂O₅ + HF → IO₂F + HIO₃

Physical properties

Iodyl fluoride forms colorless crystals of orthorhombic system.^[3] Reacts with water.^[4]

Chemical properties

Iodyl fluoride is stable in dry air, but slowly hydrolyzes to iodic and hydrofluoric acids in moisture.^[1]

IO₂F + H₂O → HIO₃ + HF

The compound reacts with strong fluorinating agents such as bromine trifluoride and selenium tetrafluoride to form iodine pentafluoride. Iodyl fluoride can be reduced to elemental iodine by pure hydrogen peroxide.^[5][6]

3 IO₂F + 4 BrF₃ → 3 IF₅ + 2 Br₂ + 3 O₂

IO₂F + 2 SeF₄ → IF₅ + 2 SeOF₂