Bergholz, Ohio
Village in Ohio, United States / From Wikipedia, the free encyclopedia
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Bergholz (/ˈbɜːrɡhoʊlz/ BURG-holes[5]) is a village in northwestern Jefferson County, Ohio, United States. The population was 544 at the 2020 census. The village's name is German and translates to "mountain timber". It is part of the Weirton–Steubenville metropolitan area.
Quick Facts Country, State ...
Bergholz, Ohio | |
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Coordinates: 40°31′11″N 80°52′50″W | |
Country | United States |
State | Ohio |
County | Jefferson |
Township | Springfield |
Area | |
• Total | 0.56 sq mi (1.46 km2) |
• Land | 0.56 sq mi (1.46 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 909 ft (277 m) |
Population (2020) | |
• Total | 544 |
• Estimate (2023)[3] | 529 |
• Density | 966.25/sq mi (372.77/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 43908 |
Area code | 740 |
FIPS code | 39-05718[4] |
GNIS feature ID | 2398100[2] |
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