Harlan Township, Fayette County, Iowa
Township in Iowa, United States / From Wikipedia, the free encyclopedia
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Harlan Township is one of twenty townships in Fayette County, Iowa. As of the 2010 census, its population was 871.[1]
Quick Facts Country, State ...
Harlan Township | |
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Coordinates: 42°46′51″N 91°54′45″W | |
Country | United States |
State | Iowa |
County | Fayette |
Area | |
• Total | 36.79 sq mi (95.28 km2) |
• Land | 36.76 sq mi (95.22 km2) |
• Water | 0.03 sq mi (0.07 km2) 0.07% |
Elevation | 1,145 ft (349 m) |
Population (2010) | |
• Total | 871 |
• Density | 24/sq mi (9.1/km2) |
Time zone | UTC-6 (CST) |
• Summer (DST) | UTC-5 (CDT) |
ZIP codes | 50655, 50662, 50681, 52142, 52164 |
GNIS feature ID | 0468005 |
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